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Adding conditional formatting and punctuation to a set of variables#1
I often need to list items separated by comma, space or punctuation, addresses are a classic example (This is overkill for an address and is for the sake of an example!):

echo "L$level, $unit/$num $street, $suburb, $state $postcode, $country.";
//ouput: L2, 1/123 Cool St, Funky Town, ABC 2000, Australia.


As simple as it sounds, is there an easy way to "conditionally" add the custom separators between variables only if the variable exists? Is it necessary to check if each variable is set? So using the above, another address with less detail may output something like:

//L, / Cool St, , ABC , .


A slightly arduous way of checking would be to see if each variable is set and display the punctuation.

if($level){ echo "L$level, "; }
if($unit){ echo "$unit"; }
if($unit && $street){ echo "/"; }
if($street){ echo "$street, "; }
if($suburb){ echo "$suburb, "; }
//etc...


It would be good to have a function that could automatically do all the stripping/formatting etc:

somefunction("$unit/$num $street, $suburb, $state $postcode, $country.");




Another example is a simple csv list. I want to output x items separated by comma:

for($i=0; $i=<5; $i++;){ echo "$i,"; }
//output: 1,2,3,4,5,


In a loop for example, what(s the best way of determining the last item of an array or the loop condition is met to not include a comma at the end of the list? One long way around this I(ve read of is to put a comma before an item, except the first entry something like:

$firstItem = true; //first item shouldn(t have comma
for($i=0; $i=<5; $i++;){
if(!$firstItem){ echo ","; }
echo "$i";
$firstItem = false;
}

posted date: 2009-04-15 05:41:00


Re: Adding conditional formatting and punctuation to a set of variables#2
I had made out the solution of this problem. click to view my topic...

hope that hepls.

posted date: 2009-04-15 05:41:01


Re: Adding conditional formatting and punctuation to a set of variables#3
Philip(s solution is probably best when working with arrays (if you don(t have to filter out empty values), but if you can(t use the array functions--for instance, when dealing with query results returned from mysqli_fetch_object()--then one solution is just a simple if statement:$list = ((;$row=mysqli_fetch_object($result);do { $list .= (empty($list) ? $row->col : ", {$row->col}");} while ($row=mysqli_fetch_object($result));Or, alternatively:do { if (isset($list)) { $list .= ", {$row->col}"; } else $list = $row->col;} while ($row=mysqli_fetch_object($result));To build a list and filter out empty values, I would write a custom function:function makeList() { $args = array_filter(func_get_args()); // as per Jon Benedicto(s answer foreach ($args as $item) { if (isset($list)) { $list .= ", $item"; } else { $list = $item; } } if (isset($list)) { return $list; } else return ((;}Then you can call it like so:$unitnum = implode((/(,array_filter(array($unit,$num)));if ($unitnum || $street) { $streetaddress = trim("$unitnum $street");} else $streetaddress = ((;if ($level) { $level = "L$level";}echo makeList($level, $streetaddress, $suburb, $state $postcode, $country).(.(;

posted date: 2009-04-15 05:52:00


Re: Adding conditional formatting and punctuation to a set of variables#4
While Phillip(s answer addresses your question, I wanted to supplement it with the following blog post by Eric Lippert. Although his discussion is in c#, it applies to any programming language.

posted date: 2009-04-15 05:56:00


Re: Adding conditional formatting and punctuation to a set of variables#5
Won't solve the problem unless you check for isset or empty before adding each element.

posted date: 2009-04-15 05:57:00


Re: Adding conditional formatting and punctuation to a set of variables#6
There(s a simple solution to your second problem:for($i=0; $i<=5; $i++) $o .= "$i,";echo chop($o, (,();

posted date: 2009-04-15 06:02:00


Re: Adding conditional formatting and punctuation to a set of variables#7
For your first example, you can use arrays in conjunction with a few of the array methods to get the desired result. For example:echo join((, (, array_filter(array("L$level", join(( (, array_filter(array(join((/(, array_filter(array($unit, $num))), $street))), $suburb, join(( (, array_filter(array($state, $postcode))), $country))) . (.(;This one-liner is quite complicated to read, so one can always wrap the array, array_filter and join calls into a separate method, and use that:function merge($delimiter){ $args = func_get_args(); array_shift($args); return join($delimiter, array_filter($args));}echo merge((, (, "L$level", merge(( (, merge((/(, $unit, $num), $street), $suburb, merge(( (, $state, $postcode), $country) . (.(;You need the array_filter calls to remove the empty entries, otherwise the delimeters would still be printed out.For your second example, add the items to an array, then use join to insert the delimeter:$arr = array();for($i=0; $i=<5; $i++){ $arr[] = $i;}echo(join((,(, $arr));

posted date: 2009-04-15 06:15:00


Re: Adding conditional formatting and punctuation to a set of variables#8
<?php $level = (foo(; $street = (bar(; $num = (num(; $unit = ((; // #1: unreadable and unelegant, with arrays $values = array(); $values[] = $level ? (L( . $level : null; // not very readable ... $values[] = $unit && $num ? $unit . (/( . $num : ($unit ? $unit : ($num ? $num : null)); $values[] = $street ? $street : null; echo join((,(, $values); // #2: or, even more unreadable and unelegant, with string concenation echo trim( ($level ? (L( . $level . (, ( : (() . ($unit && $num ? $unit . (/( . $num . (, ( : ($unit ? $unit . (, ( : ($num ? $num . (, (: (()) . ($street ? $street . (, (: (()), ( ,(); // #3: hey, i didn(t even know that worked (roughly the same as #1): echo join((, (, array( $level ? (L( . $level : null, $unit && $num ? $unit . (/( . $num : ($unit ? $unit : ($num ? $num : null)), $street ? $street : null ));?>

posted date: 2009-04-15 07:03:00


Re: Adding conditional formatting and punctuation to a set of variables#9
If I ever had to maintain your code, I would MUCH rather see something like the "arduous" method in the question. That one-line solution is uglyyyyyyyy.

posted date: 2009-04-15 07:21:00


Re: Adding conditional formatting and punctuation to a set of variables#10
+1. I'd never heard of array_filter() until now.

posted date: 2009-04-15 07:25:00


Re: Adding conditional formatting and punctuation to a set of variables#11
Just take out the last comma, i.e replace it with nothing.$string1 = "L$level, $unit/$num $street, $suburb, $state $postcode, $country.";$string1 = eregi_replace(", \.$", "\.", $string1);echo $string1;This will do the work.

posted date: 2009-04-15 07:34:00


Re: Adding conditional formatting and punctuation to a set of variables#12
although these solutions work, it seems like some long-winded code for a seemingly simple output... for a more complex arrangement it would be even hairier to get your head around these options... thanks for the contribution!

posted date: 2009-04-15 07:46:00


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